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mariamadaeva
@mariamadaeva
July 2022
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Решите задачу:
Zn+H2SO4 (9.8 г) +газ (X л)
Помогите! Срочно!
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svetka1574
Verified answer
9,8г. Х л
Zn. + H2SO4 -> ZnSO4. + H2
n=1 моль n=1моль
М=98 г/моль Vm= 22,4 л/моль
m=98г V=22,4 л
9,8 г H2SO4. - Х л Н2
98 г H2SO4. - 22,4 л Н2
V(H2)=9,8 * 22,4 / 98 = 2,24 л
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Answers & Comments
Verified answer
9,8г. Х лZn. + H2SO4 -> ZnSO4. + H2
n=1 моль n=1моль
М=98 г/моль Vm= 22,4 л/моль
m=98г V=22,4 л
9,8 г H2SO4. - Х л Н2
98 г H2SO4. - 22,4 л Н2
V(H2)=9,8 * 22,4 / 98 = 2,24 л