Решите:а) 3(а+с)² - 6ас = б) (p - 3) (p² + 3p + 9) - p³ =. Created by feiryteil. algebra-ru

Решите:а) 3(а+с)² - 6ас = б) (p - 3) (p² + 3p + 9)

July 2022 1 9 Report

Решите:

а) 3(а+с)² - 6ас =

б) (p - 3) (p² + 3p + 9) - p³ =

Answers & Comments

julyap $1) 3(a+c)^{2} -6ac=3(a ^{2} +c ^{2}+ 2ac)-6ac=3a ^{2} +3c^{2} +6ac-\\-6ac=3a^{2} +3c ^{2}$
$2)(p-3)(p ^{3} +3p+9)-p ^{3} =p ^{3} -27-p ^{3} =-27$

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