Home
О нас
Products
Services
Регистрация
Войти
Поиск
VladislavaSheko
@VladislavaSheko
October 2021
1
7
Report
Решительно 5-7, пожалуйста. Даю 30 баллов!!!
Please enter comments
Please enter your name.
Please enter the correct email address.
Agree to
terms of service
You must agree before submitting.
Send
Answers & Comments
1401Tamara
5) (x^2 - 6x + 9)/(3x - 9) : (3 - x)^2 = (x - 3)^2/3((x-3) * 1 /(3 - x)^2=
= -(3 - x)/ 3 * 1 /(3 - x)^2= - 1/3*(3 - x)
6) (4a + 2b) /(a - 3b) * (6b - 2a) / (b^2 + 4ab + 4a^2) =
= 2(2a + b) / -(3b - a) * 2(3b - a)/(2a + b)^2 = - 4/(2a + b)
7) (3x - 2x^2 - 3y + 2xy) / (x^2 - y^2) =
= [3(x - y) - 2x(x - y)] / (x -y)(x + y) =
= (x - y)(3 - 2x) / (x -y)(x + y) = (3 - 2x) / (x + y)
0 votes
Thanks 1
More Questions From This User
See All
VladislavaSheko
July 2022 | 0 Ответы
reshite pozhalujsta 1 4 primer zaranee spasibo
Answer
VladislavaSheko
October 2021 | 0 Ответы
reshite pozhalujsta ochen nadoe5888659f770012c8312de306a413a31 57742
Answer
рекомендуемые вопросы
rarrrrrrrr
August 2022 | 0 Ответы
o chem dolzhny pozabotitsya v pervuyu ochered vzroslye pri organizacionnom vyvoze n
danilarsentev
August 2022 | 0 Ответы
est dva stanka na kotoryh vypuskayut odinakovye zapchasti odin proizvodit a zapcha
myachina8
August 2022 | 0 Ответы
najti po grafiku otnoshenie v3v1 v otvetah napisano 9 no nuzhno reshenie
ydpmn7cn6w
August 2022 | 0 Ответы
Choose the correct preposition: 1.I am fond (out,of,from) literature. 2.where ar...
millermilena658
August 2022 | 0 Ответы
opredelite kak sozdavalas i kto sozdaval arabskoe gosudarstvo v kracii
MrZooM222
August 2022 | 0 Ответы
ch ajtmanov v rasskaze krasnoe yabloko ispolzuet metod rasskaz v rasskaze opi
timobila47
August 2022 | 0 Ответы
kakovo bylo naznachenie kazhdoj iz chastej vizantijskogo hrama pomogite pozhalujsta
ivanyyaremkiv
August 2022 | 0 Ответы
moment. 6....
pozhalujsta8b98a56c0152a07b8f4cbcd89aa2f01e 97513
sarvinozwakirjanova
August 2022 | 0 Ответы
pomogite pozhalusto pzha519d7eb8246a08ab0df06cc59e9dedb 6631
×
Report "Решительно 5-7, пожалуйста. Даю 30 баллов!!!..."
Your name
Email
Reason
-Select Reason-
Pornographic
Defamatory
Illegal/Unlawful
Spam
Other Terms Of Service Violation
File a copyright complaint
Description
Helpful Links
О нас
Политика конфиденциальности
Правила и условия
Copyright
Контакты
Helpful Social
Get monthly updates
Submit
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
= -(3 - x)/ 3 * 1 /(3 - x)^2= - 1/3*(3 - x)
6) (4a + 2b) /(a - 3b) * (6b - 2a) / (b^2 + 4ab + 4a^2) =
= 2(2a + b) / -(3b - a) * 2(3b - a)/(2a + b)^2 = - 4/(2a + b)
7) (3x - 2x^2 - 3y + 2xy) / (x^2 - y^2) =
= [3(x - y) - 2x(x - y)] / (x -y)(x + y) =
= (x - y)(3 - 2x) / (x -y)(x + y) = (3 - 2x) / (x + y)