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andreyishp
@andreyishp
October 2021
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решительно пожалуйста срочно номер 22 номер 22
ответ:0,94г
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хихимик
Verified answer
M(Ag) = 1,2 * 0,45 = 0,54 г
n(Ag) = 0,54 / 108 = 0,005 моль
n(AgBr) =n(Ag) = 0,005 моль
m(AgBr) = 0,005 * 188 = 0,94 г
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Answers & Comments
Verified answer
M(Ag) = 1,2 * 0,45 = 0,54 гn(Ag) = 0,54 / 108 = 0,005 моль
n(AgBr) =n(Ag) = 0,005 моль
m(AgBr) = 0,005 * 188 = 0,94 г