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няшка999
@няшка999
July 2022
1
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решите,пожалуйста)
4sin2xcos2x=1
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Chevell
4sin2xcos2x=1
sin4x=1
4x=πn, n∈z
x=(πn)/4, n∈z
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YulyaYudina
а не должна быть двойка перед sin4x=1?
YulyaYudina
т.е. 2sin4x=1
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Answers & Comments
sin4x=1
4x=πn, n∈z
x=(πn)/4, n∈z