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Miss55511
@Miss55511
August 2021
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решите,пожалуйста))):
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sedinalana
1
y`=3x²-24x+3
y``=6x-24=0
6x=24
x=4
_ +
-------------(4)--------------
y(4)=64-192+12=-116
(4;-116)
2
y`=[(4x³+2x)(x+2)-1*(4x^4+x²)]/(x+2)²=(4x^4+8x³+2x²+4x-x^4-x²)/(x+2)²=
=(3x^4+8x³+x²+4x)/(x+2)²
3
y`=3x²lnx+x³*1/x=3x²lnx+x²
y``=6xlnx+3x²*1/x+2x=6xlnx+3x+2x=6xlnx+5x
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Answers & Comments
y`=3x²-24x+3
y``=6x-24=0
6x=24
x=4
_ +
-------------(4)--------------
y(4)=64-192+12=-116
(4;-116)
2
y`=[(4x³+2x)(x+2)-1*(4x^4+x²)]/(x+2)²=(4x^4+8x³+2x²+4x-x^4-x²)/(x+2)²=
=(3x^4+8x³+x²+4x)/(x+2)²
3
y`=3x²lnx+x³*1/x=3x²lnx+x²
y``=6xlnx+3x²*1/x+2x=6xlnx+3x+2x=6xlnx+5x