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Aurélie
@Aurélie
July 2022
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решите систему уравнений
х^2-3y^2=24
x+y=8
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Answers & Comments
KiryaTushin1
X^2-3y^2=24
x=8-y
(8-y)^2-3y^2=24
64-16y+y^2-3y^2=24
-2y^2-16y+40=0
y^2+8y-20=0
d=64+80=144=12^2
y=(-8+-12)/2=-4+-6
y=2 y=-10
x=6 x=18
2 votes
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Answers & Comments
x=8-y
(8-y)^2-3y^2=24
64-16y+y^2-3y^2=24
-2y^2-16y+40=0
y^2+8y-20=0
d=64+80=144=12^2
y=(-8+-12)/2=-4+-6
y=2 y=-10
x=6 x=18