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lizazinich
@lizazinich
August 2022
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Розкладіть на множники квадратний тричлен : а) 2x²+8х-10 б) -x²+4х-3
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kirichekov
Verified answer
Ax²+bx+c=a*(x-x₁)*(x-x₂)
a).
2x²+8x-10=2*(x+5)(x-1)
2x²+8x-10=0
D=144
x₁=-5, x₂=1
b).
-x²+4x-3=-(x-3)(x-1)
-x²+4x-3=0
D=4
x₁=3, x₂=1
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lizazinich
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Answers & Comments
Verified answer
Ax²+bx+c=a*(x-x₁)*(x-x₂)a).2x²+8x-10=2*(x+5)(x-1)
2x²+8x-10=0
D=144
x₁=-5, x₂=1
b). -x²+4x-3=-(x-3)(x-1)
-x²+4x-3=0
D=4
x₁=3, x₂=1