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mickeymouse228
@mickeymouse228
July 2022
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Розкласти на множники
2p^2 - 7p+6 = 0
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nafanya2014
Verified answer
2p² - 7p+6 = 0
D=(-7)²-4·2·6=49-48=1
p₁=(7-1)/4=3/2 или р₂=(7+1)/4=2
2p² - 7p+6=2(р-3/2)(р-2)
или
внесем 2 в первую скобку
2p² - 7p+6=(2р-3)(р-2)
3 votes
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Answers & Comments
Verified answer
2p² - 7p+6 = 0D=(-7)²-4·2·6=49-48=1
p₁=(7-1)/4=3/2 или р₂=(7+1)/4=2
2p² - 7p+6=2(р-3/2)(р-2)
или
внесем 2 в первую скобку
2p² - 7p+6=(2р-3)(р-2)