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frolo9823
@frolo9823
July 2022
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Розв'язати нерівність: (2x-3)(x+1)≥x²+9
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skvrttt
2x²+2x-3x-3-x²-9≥0
x²-x-12≥0
x1+x2=1 U x1*x2=-12
x1=-3 u x2=4
+ _ +
-------------[-3]------------------[4]---------------------
x∈(-∞;-3] U [4;∞)
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sedinalana
Verified answer
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Answers & Comments
x²-x-12≥0
x1+x2=1 U x1*x2=-12
x1=-3 u x2=4
+ _ +
-------------[-3]------------------[4]---------------------
x∈(-∞;-3] U [4;∞)
Verified answer