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nasta1005
@nasta1005
August 2022
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розв'яжіть рівняння y'=0 якщо y=cosx+xsinx+2sinx
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yurtin
(cosx)'=-sinx;
(sinx)'=cos;
(xsinx)'=sinx+xcosx;
y'(x)=-sinx+sinx+xcosx+2cosx;
(2+x)cosx=0;
2+x=0 или cosx=0;
x=-2 ; x=Pi/2+Pi*n.
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Answers & Comments
(sinx)'=cos;
(xsinx)'=sinx+xcosx;
y'(x)=-sinx+sinx+xcosx+2cosx;
(2+x)cosx=0;
2+x=0 или cosx=0;
x=-2 ; x=Pi/2+Pi*n.