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vasileewa
@vasileewa
July 2022
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с какими из перечисленных веществ будет реагировать оксид серы (IV) : BeO Cl2 O2 NaOH H2O Zn?
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svetka1574
Verified answer
SO2 + BeO -> BeSO3
2SO2 + O2 -> 2SO3
SO2 + 2NaOH -> Na2SO3 + H2O
SO2 + H2O -> H2SO3
3 votes
Thanks 2
mrvladimir2
Verified answer
SO2 + BeO = BeSO3
2SO2 + O2 = 2SO3
SO2 + 2NaOH = Na2SO3 + H2O
SO2 + H2O = H2SO3
1 votes
Thanks 1
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Answers & Comments
Verified answer
SO2 + BeO -> BeSO32SO2 + O2 -> 2SO3
SO2 + 2NaOH -> Na2SO3 + H2O
SO2 + H2O -> H2SO3
Verified answer
SO2 + BeO = BeSO32SO2 + O2 = 2SO3
SO2 + 2NaOH = Na2SO3 + H2O
SO2 + H2O = H2SO3