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eric666cartman
@eric666cartman
August 2022
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С какой скоростью должна лететь бронебойная пуля массой 0,15 кг , чтобы обладать кинетической энергией 6,75 кДж ?
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fatt52
Verified answer
W=mv²/2
v=√(2*W/m)=√(2*6.75*10^3/0.15)=300 м/с
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Answers & Comments
Verified answer
W=mv²/2
v=√(2*W/m)=√(2*6.75*10^3/0.15)=300 м/с