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LOLOLOLOLo1232
@LOLOLOLOLo1232
July 2022
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Определить кинетическую энергию (MэВ) электрона, если её скорость равна 2,4*108 м/с. me=9,1*10-31 кг.
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naf52NAF
Verified answer
Ек=mv²/2=9,1*10⁻³¹*(2,4*10⁸)²/2=9,1*10⁻³¹*5,76*10¹⁶/2=
9,1*10⁻
¹⁵*2,88=26,208*10⁻¹⁵ Дж
3 votes
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Answers & Comments
Verified answer
Ек=mv²/2=9,1*10⁻³¹*(2,4*10⁸)²/2=9,1*10⁻³¹*5,76*10¹⁶/2=9,1*10⁻¹⁵*2,88=26,208*10⁻¹⁵ Дж0,355
0,441
0,330