p=1.01*10^5 Па v=550 м/с ро=?
p=(1/3)*n*mo*v²=(1/3)*po*v²
po=3*p/v²=3*1.01*10^5/550²≈1.002 кг/м³
=======================
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
Verified answer
p=1.01*10^5 Па v=550 м/с ро=?
p=(1/3)*n*mo*v²=(1/3)*po*v²
po=3*p/v²=3*1.01*10^5/550²≈1.002 кг/м³
=======================