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кул7
@кул7
July 2022
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С объяснением пожалуйста, ............ё
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iknowthatyoufeelbro
Z(2+i)=3-i
z = (3-i) / (2+i)
z = (3-i) * (2-i) / ((2+i)*(2-i))
z = (6 - 2i - 3i + i^2) / (2^2 - i^2)
z = (5 - 5i) / 5 = 1 - i
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Answers & Comments
z = (3-i) / (2+i)
z = (3-i) * (2-i) / ((2+i)*(2-i))
z = (6 - 2i - 3i + i^2) / (2^2 - i^2)
z = (5 - 5i) / 5 = 1 - i