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66sam99
@66sam99
June 2022
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На поверхности планеты ускорение свободного падения равно 1,6 м/с^2, а ее первая космическая скорость 2,56 км/с. Определите радиус этой планеты.
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Verified answer
V^2/R=g
R=v^2/g=v^2/g=
(2,56*10^3)^2
/1,6 м =
4096000
м= 4096км
7 votes
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Verified answer
V^2/R=gR=v^2/g=v^2/g=(2,56*10^3)^2/1,6 м = 4096000м= 4096км