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DEADЕYE
@DEADЕYE
August 2022
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с помощью цикла while вычислить y=2x^2-3x+4 x[-5;4], h=2
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DragonetSoul
Program Z;
var x, y: real;
h:integer;
Begin
h:=2;
x:=-5;
while (x<=4) do begin
y:=2*sqr(x)-3*x+4;
writeln('y=',y, ' ', 'x=', x);
x:=x+h;
end;
End.
2 votes
Thanks 1
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Answers & Comments
var x, y: real;
h:integer;
Begin
h:=2;
x:=-5;
while (x<=4) do begin
y:=2*sqr(x)-3*x+4;
writeln('y=',y, ' ', 'x=', x);
x:=x+h;
end;
End.