Дано:
υ0 = 420 м/с
s = 20 м
t - ?
Решение:
s = (υ² - υ0²)/(2a)
υ = 0 => s = -υ0²/(2a)
a = -υ0²/(2s)
υ = υ0 + at
0 = υ0 - υ0²/(2s)*t
υ0 = υ0²/(2s)*t | : υ0
1 = υ0/(2s)*t
t = 1/(υ0/(2s)) = 2s/υ0 = 2*20/420 = 40/420 = 4/42 = 1/21 = 0,04761904762 = 0,05 c
Ответ: 0,05 с.
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Answers & Comments
Дано:
υ0 = 420 м/с
s = 20 м
t - ?
Решение:
s = (υ² - υ0²)/(2a)
υ = 0 => s = -υ0²/(2a)
a = -υ0²/(2s)
υ = υ0 + at
0 = υ0 - υ0²/(2s)*t
υ0 = υ0²/(2s)*t | : υ0
1 = υ0/(2s)*t
t = 1/(υ0/(2s)) = 2s/υ0 = 2*20/420 = 40/420 = 4/42 = 1/21 = 0,04761904762 = 0,05 c
Ответ: 0,05 с.