v1=15.5 м/с v2=12.5 м/с s=600 м a=? t=?
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s=(v2²-v1²)/(2*a)
a=(v2²-v1²)/(2*s)=(12.5²-15.5²)/(2*600)= - 0.07 м/с²
a=(v2-v1)/t
t=(v2-v1)/a=(12.5-15.5/(-0.07)≈43 c
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Verified answer
v1=15.5 м/с v2=12.5 м/с s=600 м a=? t=?
===
s=(v2²-v1²)/(2*a)
a=(v2²-v1²)/(2*s)=(12.5²-15.5²)/(2*600)= - 0.07 м/с²
a=(v2-v1)/t
t=(v2-v1)/a=(12.5-15.5/(-0.07)≈43 c
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