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Egorakr
@Egorakr
September 2021
2
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Мяч падает с высоты 25 м. На какой высоте скорость его движения будет равна 20 м/с?
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Answers & Comments
Saggitarius29
ЗСЭ: Ep = Ep1 + Ek,
m g h = m g h1 + m v^2 / 2,
g h = (2 g h1 + v^2),
h1 = (2 g h - v^2) / 2g,
h1 = h - v^2 / 2g,
h1 = 25 - 400 / 20 = 5 м
4 votes
Thanks 5
UmbertoVargas
Verified answer
V=gt
t=v/g=2c
s1=(gt^2)/2=20м
s2=s-s1=5м
3 votes
Thanks 5
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Answers & Comments
m g h = m g h1 + m v^2 / 2,
g h = (2 g h1 + v^2),
h1 = (2 g h - v^2) / 2g,
h1 = h - v^2 / 2g,
h1 = 25 - 400 / 20 = 5 м
Verified answer
V=gtt=v/g=2c
s1=(gt^2)/2=20м
s2=s-s1=5м