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Гаухар01
@Гаухар01
July 2022
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S1=1+2+...+99
S2=3+6+9+...+99
s=?
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ShirokovP
Verified answer
Дано:
S1 = 1+2+...+99
a1 = 1
a2 = 2
d = a2 - a1 = 1
n = 99
Найти:
S99
Решение:
S99 = (a1+ a99)/2*99 = (1 + 99)*49,5 = 4950
================================
S2 = 3 + 6 + 9 + ... + 99
a1 = 3
a2 = 6
d = 3
a33 = 99
S33 = (a1 + a33)/2* 33 = 16,5* (3 + 99) = 1683
2 votes
Thanks 3
Гаухар01
ты мой спаситель
Гаухар01
Спасибо ☺️
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Answers & Comments
Verified answer
Дано:S1 = 1+2+...+99
a1 = 1
a2 = 2
d = a2 - a1 = 1
n = 99
Найти:
S99
Решение:
S99 = (a1+ a99)/2*99 = (1 + 99)*49,5 = 4950
================================
S2 = 3 + 6 + 9 + ... + 99
a1 = 3
a2 = 6
d = 3
a33 = 99
S33 = (a1 + a33)/2* 33 = 16,5* (3 + 99) = 1683