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albinas11
@albinas11
July 2022
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S12 a1=-3 a3*a7=24 помогите пожалуйста
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Clash121
A1=-3
a3*a7=24
(a1+2d)(a1+6d)=24
(-3+2d)(-3+6d)=24
9-19d-6d+12d^2=24
12d^2-24d-15=0I÷3
4d^2-8d-5=0
D=64-4*4*(-5)=144
d1=2,5
d2=0,5
S12 = ( a1+a12)*12/2=(2a1 +11d)*6
S12(1)=(2*(-3)+11*2,5)*6=129
S12(2)=(2*(-3)+11*(-0,5))*6=69
Ответ: 129;69.
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Answers & Comments
a3*a7=24
(a1+2d)(a1+6d)=24
(-3+2d)(-3+6d)=24
9-19d-6d+12d^2=24
12d^2-24d-15=0I÷3
4d^2-8d-5=0
D=64-4*4*(-5)=144
d1=2,5
d2=0,5
S12 = ( a1+a12)*12/2=(2a1 +11d)*6
S12(1)=(2*(-3)+11*2,5)*6=129
S12(2)=(2*(-3)+11*(-0,5))*6=69
Ответ: 129;69.