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lizaburdyukova
@lizaburdyukova
July 2022
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Тело массой 1 кг колеблется на пружине с амплитудой 0,02 м. Максимальное ускорение тела равно 0,3 м/с2. Определите полную механическую энергию колебаний.
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sokolovvovikn
Verified answer
E=k*xm^2/2
m*am=k*xm
E=m*am*xm/2=1*0,3*0,02/2=0,003 Дж
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Answers & Comments
Verified answer
E=k*xm^2/2m*am=k*xm
E=m*am*xm/2=1*0,3*0,02/2=0,003 Дж