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thatlinakid
@thatlinakid
October 2021
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На участке пути автобус движется с ускорением 1,25м/с2 определите силу тяги, если масса автобуса 10 000 кг, а коэффициент трения 0,2
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tana20101997
Verified answer
M*a=F-k*m*g
F=m*a+k*m*g=m*(a+k*g)=10 000*(1,25*0,2*9,8)=32100 H
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Verified answer
M*a=F-k*m*gF=m*a+k*m*g=m*(a+k*g)=10 000*(1,25*0,2*9,8)=32100 H