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12345wewe
@12345wewe
August 2022
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Найдите период колебаний математического маятника длиной 2 м на экваторе. Ускорение свободного падения принять равным 9, 78 м/с^2
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MuurMuusyaa
Т=2П×"корень"(l/g). T=3,14×2×"корень"(2/9,78)=3,14×2×0,45=2,826с
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