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coolneol
@coolneol
April 2021
2
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Шайба, имея начальную скорость 12 м/с,скользит по льду с ускорением 0,6 м/с^2.Каков тормозной путь шайбы?
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sokolovvovikn
Verified answer
S=(V^2-V0)2/2*a V=0 a<0
S=V0^2/2*a=12^2/2*0,6=120 м
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kadavris
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Verified answer
S=(V^2-V0)2/2*a V=0 a<0S=V0^2/2*a=12^2/2*0,6=120 м
(м)