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achivi15
@achivi15
July 2022
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С2.Поможете мне?Я не справляюсь, вот задачка.Найти производную сложной функции y=ln x в 3 степени
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Dимасuk
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Пусть u = x³, v = lnu
y' = u'•v' = (x³)'•(lnu)' = 3x²•(1/u) = 3x²•(1/x³) = 3/x
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Answers & Comments
Verified answer
Пусть u = x³, v = lnuy' = u'•v' = (x³)'•(lnu)' = 3x²•(1/u) = 3x²•(1/x³) = 3/x