Объяснение:
S3=104
q=6
b1=?
Sn=(b1(1-q^n)) /(1-q)
S3=(b1(1-6³))/(1-6)
104=(b1(1-216))/(-5)
-215•b1=104•(-5)
-215•b1= -520
b1=520/215=104/43=2 18/43
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Объяснение:
S3=104
q=6
b1=?
Sn=(b1(1-q^n)) /(1-q)
S3=(b1(1-6³))/(1-6)
104=(b1(1-216))/(-5)
-215•b1=104•(-5)
-215•b1= -520
b1=520/215=104/43=2 18/43