Дано:
m(Ae)=7.8г
m(Ae2s3)=26 г
w(примесей)-?
2Ae+3S→Ae2s3
m(Ae)=M⚹ν=27/моль⚹2моль=25 г
m(Ae2S3)=M⚹ν=(54+96 г/моль⚹1=150 г
x2/S4 2=
Помогите до решать задачу
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