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maxoties2001
@maxoties2001
July 2022
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сахар массой 12,5 г растворили в 112,5 воды.определите массовую долю сахара в полученом растворе.
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skypatch
Verified answer
M(р-ра)=m(в-ва)+m(воды)=12,5+112,5=125
ω=m(в-ва)*100%/m(р-ра)=12,5*100/125=10%
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Verified answer
M(р-ра)=m(в-ва)+m(воды)=12,5+112,5=125ω=m(в-ва)*100%/m(р-ра)=12,5*100/125=10%