3^(log(3)4)=4
log(4)x=t
t^2-3t=4
t^2-3t-4=0
D=9+16=25
t1=(3+5)/2=4; log(4)x=4; x1=4^4=256
t2=(3-5)/2=-1;log(4)x=-1;x2=4^(-1)=1/4
Ответ x={1/4;256}
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3^(log(3)4)=4
log(4)x=t
t^2-3t=4
t^2-3t-4=0
D=9+16=25
t1=(3+5)/2=4; log(4)x=4; x1=4^4=256
t2=(3-5)/2=-1;log(4)x=-1;x2=4^(-1)=1/4
Ответ x={1/4;256}