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adeksandrshuva
@adeksandrshuva
August 2022
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При какой температуре средняя квадратичная скорость движения молекул
водорода равна 2000м/с
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solvo
v=2000м/с, M=0,002 кг/ моль. Т-?
v=√(3RT/M), v²=
3RT/M, T=Mv²/(3R),
T=0,002*4*10^6/(3*8,31) = 321 К.
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Answers & Comments
v=√(3RT/M), v²= 3RT/M, T=Mv²/(3R),
T=0,002*4*10^6/(3*8,31) = 321 К.