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drygrss1
@drygrss1
July 2022
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Сделайте пожалуйста очень срочно
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makuzkinap195y6
1. a) y'=4x+3.
б) у'=-2(1+х^2)+2х(3-2х)=-2-2х^2+6х-4х^2= -6х^2+6х-2.
в) у'=(2х(х^2+1)-2х(х^2-1))/(х^2+1)^2= 4х/(х^2+1)^2.
г) у'=(х^(1+2/3))'=(х^(5/3))'=5/3 · х^(2/3).
2. у'=5х^4+2.
У'(хо)=у'(1)=5+2=7.
0 votes
Thanks 1
sedinalana
1
1)y`=4x+3
2)-2(1+x²)+2x(3-2x)=-2-2x²+6x-4x²=-2+6x-6x²
3)(2x(x²+1)-2x(x²-1))/(x²+1)²=(2x³+2x-2x³+2x)/(x²+1)²=4x/(x²+1)²
4
y=x^5/3
y`=5/3*x^2/3=5∛x²/3
2
y`=5x^4+2
y`(1)=5*1+2=5+2=7
1 votes
Thanks 1
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Answers & Comments
б) у'=-2(1+х^2)+2х(3-2х)=-2-2х^2+6х-4х^2= -6х^2+6х-2.
в) у'=(2х(х^2+1)-2х(х^2-1))/(х^2+1)^2= 4х/(х^2+1)^2.
г) у'=(х^(1+2/3))'=(х^(5/3))'=5/3 · х^(2/3).
2. у'=5х^4+2.
У'(хо)=у'(1)=5+2=7.
1)y`=4x+3
2)-2(1+x²)+2x(3-2x)=-2-2x²+6x-4x²=-2+6x-6x²
3)(2x(x²+1)-2x(x²-1))/(x²+1)²=(2x³+2x-2x³+2x)/(x²+1)²=4x/(x²+1)²
4
y=x^5/3
y`=5/3*x^2/3=5∛x²/3
2
y`=5x^4+2
y`(1)=5*1+2=5+2=7