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mirza23
@mirza23
August 2022
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Sdelayte 85 nomer s resheniyem plsss!!!
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chepyh
Sina = b/c; cosa= a/c
tgB=b/a;
sin2a = 2sinacosa = 2*(b/c)(a/c)
sin2a*tgB=2*(b/c)(a/c)*(b/a)=(2b^2*a/c^2*a)=(2b^2/c^2)
Ответ: D) 2b^2/c^2
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mirza23
Bolshoye spasibo!!
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Answers & Comments
tgB=b/a;
sin2a = 2sinacosa = 2*(b/c)(a/c)
sin2a*tgB=2*(b/c)(a/c)*(b/a)=(2b^2*a/c^2*a)=(2b^2/c^2)
Ответ: D) 2b^2/c^2