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Yara06
@Yara06
August 2022
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При какой температуре средняя квадратичная скорость электрона равна 2*10^5 м/с?
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tana20101997
Verified answer
T=n*V^2/3*k=9,1*10^-31*4*10^10/3*1,38*10^-23=879 K
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Verified answer
T=n*V^2/3*k=9,1*10^-31*4*10^10/3*1,38*10^-23=879 K