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Angelowek01nurgul
@Angelowek01nurgul
March 2022
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(sin альфа+cos альфа)2+(sin альфа -cos альфа )2
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Эксперт5
Verified answer
(sina+cosa)²+(sina-cosa)²=
=sin²a+2sina*cosa+cos²a+sin²a-2sina*cosa+cos²a=
=2sin²a+2cos²a=2(sin²a+cos²a)=2*1=2
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Verified answer
(sina+cosa)²+(sina-cosa)²==sin²a+2sina*cosa+cos²a+sin²a-2sina*cosa+cos²a=
=2sin²a+2cos²a=2(sin²a+cos²a)=2*1=2