sin135×cos120×tg405×ctg330×cos560=?...

August 2022 1 5 Report

sin135×cos120×tg405×ctg330×cos560=?

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$\sin 135\textdegree\cdot\cos120\textdegree\cdot tg405\textdegree\cdot ctg330\textdegree\cdot\cos560\textdegree=\\\\=\sin \big(180\textdegree-45\textdegree\big)\cdot\cos\big(180\textdegree-60\textdegree\big)\cdot tg\big(360\textdegree+45\textdegree\big)\times\\\\~~~~~~\times ctg\big(360\textdegree-30\textdegree\big)\cdot\cos\big(360\textdegree+180\textdegree+20\textdegree\big)=$

$=\sin 45\textdegree\cdot\big(-\cos60\textdegree\big)\cdot tg45\textdegree\cdot \big(-ctg30\textdegree\big)\cdot\big(-\cos20\textdegree\big)=\\\\=\dfrac{\sqrt2}2\cdot \bigg(-\dfrac 12\bigg)\cdot 1\cdot \Big(-\sqrt3\Big)\cdot\big(-\cos20\textdegree\big)=\\\\\boldsymbol{=-\dfrac{\sqrt6}4\cdot\cos20\textdegree}$

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