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философ16
@философ16
March 2022
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sin13°cos3°-sin5°sin85°-cos8°cos82°
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iknowthatyoufeelbro
Sin13°cos3°-sin5°sin85°-cos8°cos82°=
sin13°cos3°-sin5°cos(90°-85°)-cos8°sin(90°-82°)=
sin13°cos3°-(2sin5°cos5°+2cos8°sin8°)/2=
sin13°cos3°-(sin10°+sin16°)/2=
sin13°cos3°-(sin(13°-3°)+sin(13°+3°))/2=
sin13°cos3°-(sin13°cos3°-cos13°sin3°+sin13°cos3°+cos13°sin3°)/2=
sin13°cos3°-(2sin13°cos3°)/2=
sin13°cos3°-sin13°cos3°=0
2 votes
Thanks 4
bearcab
Начиная с четвертой строки можно было применить формулу произведения синуса на косинус. Так вроде стандартнее, на мой взгляд. Хотя... и Ваше решение неплохо. Только нужно догадаться))
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Answers & Comments
sin13°cos3°-sin5°cos(90°-85°)-cos8°sin(90°-82°)=
sin13°cos3°-(2sin5°cos5°+2cos8°sin8°)/2=
sin13°cos3°-(sin10°+sin16°)/2=
sin13°cos3°-(sin(13°-3°)+sin(13°+3°))/2=
sin13°cos3°-(sin13°cos3°-cos13°sin3°+sin13°cos3°+cos13°sin3°)/2=
sin13°cos3°-(2sin13°cos3°)/2=
sin13°cos3°-sin13°cos3°=0