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sarmy8404
@sarmy8404
April 2023
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Решить:
sin^2(-330°)-cos^2(-120°)-tg^2(-240°)-ctg^2(-330°)=
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fenix6810
sin^2(-330°)-cos^2(-120°)-tg^2(-240°)-ctg^2(-330°)=
=sin^2(30)-cos^2(60)-tg^2(60)-ctg^2(30)=
=sin^2(30)-sin^2(30-2tg^2(60)=-6
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=sin^2(30)-cos^2(60)-tg^2(60)-ctg^2(30)=
=sin^2(30)-sin^2(30-2tg^2(60)=-6