sin^2 x + 2 sin (π - x) cos x - 3 cos^2 (2π - x) = 0. Created by oleg1836. algebra-ru

sin^2 x + 2 sin (π - x) cos x - 3 cos^2 (2π

June 2022 1 10 Report

sin^2 x + 2 sin (π - x) cos x - 3 cos^2 (2π - x) = 0

Answers & Comments

bayd Sin^2 x + 2 sin (π - x) * cos x - 3 cos^2 (2π - x) = 0
sin² x + 2 sin x * cos x - 3 cos² x = 0

Пояснение: sin (pi - x) = sin x cos² (2pi - x) = cos² x

sin² x + 2 sin x * cos x - 3 cos² x = 0 | : cos²x ≠ 0
tg² x + 2 tg x - 3 = 0
Вводим замену tg x = t
Решаем квадратное уравнение
t² + 2t - 3 = 0
D = b² - 4ac = 2² - (-4*1*3) = 4 + 12 = 16 √D = 4
t1 = (-2+4)/2 = 1
t2 = (-2-4)/2 = -3

tg x = t
1) tg x = 1
x = pi/4 + pik, k ∈ Z

2) tg x = -3
x = -arctg3 + pik, k ∈ Z

ОТВЕТ: pi/4 + pik, k ∈ Z; -arctg3 + pik, k ∈ Z

3 votes Thanks 3

Answers & Comments

horda v geometrii pozhalujsta pomogite

organicheskoe veshestvo imeet plotnost po oksidu sery iv 1344 pri szhiganii 0

tex kl3a660f7d6b3767157a43abcbb5699274 34618

na cokole avtomobilno lampochki napisano 20 vt 12 v kakuyu rabotu sovershit e

pri soprotivlenii reostata 1 om napryazhenie na zazhimah istochnika toka bylo 15 v

sila toka v katushke umenshilas s 16 do 12 a pri etom energiya eyo magnitnogo pol

elektron i proton vletayut v odnorodnoe magnitnoe pole perpendikulyarno vektoru ma6a2a6ba6763d69aed5c172bfd2792d6e 71653

maksimalnoe napryazhenie na kondensatore kolebatelnogo kontura sostavlyaet 90 v

2 - x) - 1 = 0...

na risunke 12 izobrazhyon uchastok cepi soderzhashij rezistory soprotivleniyami r1

рекомендуемые вопросы

Helpful Links

Helpful Social