sin²(270°-α) + sin²(360°-α) = (-cos α)² + (sin (-α))² =
= cos²α + (-sin α)² = cos²α + sin²α = 1
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Использованы формулы
sin (270°-α) = -cos α
sin (-α) = -sin α
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Verified answer
sin²(270°-α) + sin²(360°-α) = (-cos α)² + (sin (-α))² =
= cos²α + (-sin α)² = cos²α + sin²α = 1
================================
Использованы формулы
sin (270°-α) = -cos α
sin (-α) = -sin α