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jakuasilbek
@jakuasilbek
September 2021
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sin22cos8+cos158cos98
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nafanya2014
Verified answer
sin22°·cos8°+cos158°·cos98
°=sin22°·cos8°+cos(180°-158°)·cos(90°+8°)=
=sin22°·cos8°+(-cos22°)·(-sin8°)=sin22°·cos8°+cos22°·sin8°=
=sin (22°+8°)=sin30°=1/2=0,5
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Verified answer
sin22°·cos8°+cos158°·cos98°=sin22°·cos8°+cos(180°-158°)·cos(90°+8°)==sin22°·cos8°+(-cos22°)·(-sin8°)=sin22°·cos8°+cos22°·sin8°=
=sin (22°+8°)=sin30°=1/2=0,5