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qwegol
@qwegol
August 2022
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sin^2(2x)-4sin^2( x)
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JeBei
(2sinxcosx)^2-4sin^2(x)=4sin^2(x)cos^2(x)-4sin^2(x)=4sin^2(x)*(cos^2(x)-1)=
=-4sin^2(x)*(1-cos^2(x))=-4sin^3(x)
2 votes
Thanks 2
qwegol
спасибо
JeBei
да не за что
qwegol
неправельно -4sin^4(x)будет
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Answers & Comments
=-4sin^2(x)*(1-cos^2(x))=-4sin^3(x)