Упростить выражение:
(cos2α-cos6α+cos10α-cos14α)/(sin2α+sin6α+sin10α+sin14α)
(cos1a-cos3a+cos5a-cos7a)/(sin1a+sin3a+sin5a+sin7a)
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Answers & Comments
=sin2a/cos2a
=tan2a
(cos1a-cos3a+cos5a-cos7a)/(sin1a+sin3a+sin5a+sin7a)