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frankydavidov
@frankydavidov
July 2022
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sin^2(pi+t)+cos^2(2pi-t)=0
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sedinalana
Verified answer
Sin²(π+t)+cos²(2π-t)=0
sin²t+cos²t=1
1≠0
--------------------------
sin(π+t)=-sint
cos(2π-t)=cost
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Answers & Comments
Verified answer
Sin²(π+t)+cos²(2π-t)=0sin²t+cos²t=1
1≠0
--------------------------
sin(π+t)=-sint
cos(2π-t)=cost