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кристинка03010313
@кристинка03010313
July 2022
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Помогите, срочно!!!
1) y= sin2x/cos2x
2) у= x^2+1/sin2x
найти производную
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JuliaSWS
1) y= sin2x/cos2x
y'=(2cos2x*cos2x+2sin2x*sin2x)\((cos2x)^2)
2) у= x^2+1/sin2x
y'=2+(sinx-cosx)\((sinx)^2)
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Answers & Comments
y'=(2cos2x*cos2x+2sin2x*sin2x)\((cos2x)^2)
2) у= x^2+1/sin2x
y'=2+(sinx-cosx)\((sinx)^2)