sin2x-cosx=0
2sinxcosx-cosx=0
cosx(2sinx-1)=0
2 случая
1) cosx=0
x=pi/2+pik, k∈Z
2) 2sinx-1=0
sinx=1/2
x=pi/6+2pik, k∈Z
x=5pi/6+2pik, k∈Z
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Answers & Comments
sin2x-cosx=0
2sinxcosx-cosx=0
cosx(2sinx-1)=0
2 случая
1) cosx=0
x=pi/2+pik, k∈Z
2) 2sinx-1=0
sinx=1/2
x=pi/6+2pik, k∈Z
x=5pi/6+2pik, k∈Z