Ответ:

sin^2x+sin2x=1

sin^2x+2sinxcosx-1=0

sin^2x+2sinxcosx-sin^2x-cos^2x=0

2sinxcosx-cos^2x=0

cosx(2sinx-cosx)=0

1)cosx=0,x=π/2+πk,k-Z

2)2sinx-cosx=0

2sinx=cosx |:cosx

2tgx=1

tgx=1/2

x=arctg1/2+πn,n-Z