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dashkaerchel
@dashkaerchel
July 2022
1
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sin2x+sin*(Pi-8x)=√2*Cos3x
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shakera2004
2sin5xcos3x-√2cos3x=02cos3x(sin5x-√2/2)=0cos3x=0⇒3x=π/2+πn⇒x=π/6+πn/3sin5x=√2/2⇒5x=(1)^n*π/4+πn⇒x=(-1)^n*π/20+πn/5
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